Stefan Corneliu Petrea wsdookadr

Make Ubuntu packages 90% faster by rebuilding them

TL;DR

You can take the same source code package that Ubuntu uses to build jq, compile it again, and realize 90% better performance.

Setting

I use jq for processing GeoJSON files and other open data offered in JSON format. Today I am working with a 500MB GeoJSON file that contains the Alameda County Assessor's parcel map. I want to run a query that prints the city for every parcel worth more than a threshold amount. The program is

software (with binary)

py-based

movie torrent sites:

search engines:

https://www.limetorrents.lol/

reverse dependencies for Python

nitter.it (for twitter)
scribe.rip (for medium.com)
yewtu.be (for youtube.com; more instances here)
teddit.net (for reddit.com)
safereddit.com

larger list available here

Problem

The official Elasticsearch documentation site is protected with Cloudflare Captcha so it can't be directly scraped.

The built-docs repo isn't self-contained (there are external resources, both images and js) and I don't understand how their air_gapped docs work, nor are there instructions on how to use it.

	#!/usr/bin/env python
	"""
	Upstream: https://gist.github.com/kylemanna/5692543
	Blog post: https://blog.kylemanna.com/linux/parse-emmc-extended-csd-ecsd-registers-with-python/

	Description: Get eMMC health information
	Tested on ASUS T100TA
	Example:

	root@fedora:/home/user# ./emmc_health.py \| rg -i 'LIFE\|HEALTH\|EOL'

	services:
	r1:
	image: alpine:3.20.3
	tty: true
	#command: /bin/sh -c "/bin/cat"
	volumes:
	- type: tmpfs
	target: /logs
	tmpfs:
	size: "4294967296"

	#!/usr/bin/python3

	# mawk's problem statement:
	# the original question is: how many 6-sided (numbered from 1 to 6) fair dice are needed so that you can form 936 different products of the results?
	# with 2 dice you can form the products 1·1, 1·2, …, 6·6
	# the issue of course here is that 4 = 2² and 6 = 2·3
	# if the dice were numbered with 1 2 3 5 7 11 it would be much easier

	S=set([])
	D=156

	#!/bin/bash
	# same without cropping or merging

	PDF="$1"
	rm -rf A B C
	mkdir A B C 2>/dev/null
	pdftk $PDF burst output A/%04d.pdf
	find A/*.pdf \| xargs -P5 -I{} bash -c '
	a={};
	b=$(echo $a \| sed -e "s/pdf/png/g" \| sed -e "s/^A/B/g");