2013-03 slc.rb problem 1

greatest_product.txt

Find the greatest product of five consecutive digits in the 1000-digit number.

Make a program that recieves a string of numbers (see below) and outputs the answer

73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450

This is Matt and Max's solution:

describe "greatest product" do
context "calc method" do
it "should return product of 5 digits" do
str = "12345"
val = 1 * 2 * 3 * 4 * 5

 calc_product(str).should == val

end

it "should iterate through list 5 char chunks of a str" do
str = "23456"
lists = get_str_lists(str)
lists.length.should == 1
lists[0].should == str
end

it "should iterate through list 5 char chunks of a str" do
 str = "23456789"
 lists = get_str_lists(str)
 lists.length.should == 4
 lists[0].should == "23456"
 lists[1].should == '34567'
 lists[2].should == '45678'
 lists[3].should == '56789'
end

it "should return the largest value" do
  str = "23456789"
  val = 5*6*7*8*9
  run(str).should == val
end

end
end

def get_str_lists(str)
list = []
index = 0
while index <= str.length-5
list << str.slice(index, 5)
index += 1
end
list
end

def calc_product(str)
start_idx = 0
i=1
str.split('').each{|ii| i = i*ii.to_i}
i
end

def run(str)
lists = get_str_lists(str)
val = 0
lists.each do |l|
tmp = calc_product(l)
if tmp > val
val = tmp
end
end
val
end

puts run("73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450".strip)

# Decompose first arg into first five elements a,b,c,d,e
# and xs is the remaining elements
def products ((a,b,c,d,e,*xs), hi)
  return hi if e.nil? #return hi if we only have 4 elements left
  prod = [a,b,c,d,e].reduce(&:*) #Multiply a, b, c, d, and e

  # Recursively call products
  # Passing the first arg with one less element
  # And the max of prod or hi
  products([b,c,d,e]+xs, [prod, hi].max)
end

# Map the characters into ints
ints = DATA.read.chars.map(&:to_i)

# Call products with the ints and initial max of 0
p products(ints, 0)

# Everything after __END__ is available as DATA
__END__
7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450

ubernumber = 
"73167176531330624919225119674426574742355349194934"+
"96983520312774506326239578318016984801869478851843"+
"85861560789112949495459501737958331952853208805511"+
"12540698747158523863050715693290963295227443043557"+
"66896648950445244523161731856403098711121722383113"+
"62229893423380308135336276614282806444486645238749"+
"30358907296290491560440772390713810515859307960866"+
"70172427121883998797908792274921901699720888093776"+
"65727333001053367881220235421809751254540594752243"+
"52584907711670556013604839586446706324415722155397"+
"53697817977846174064955149290862569321978468622482"+
"83972241375657056057490261407972968652414535100474"+
"82166370484403199890008895243450658541227588666881"+
"16427171479924442928230863465674813919123162824586"+
"17866458359124566529476545682848912883142607690042"+
"24219022671055626321111109370544217506941658960408"+
"07198403850962455444362981230987879927244284909188"+
"84580156166097919133875499200524063689912560717606"+
"05886116467109405077541002256983155200055935729725"+
"71636269561882670428252483600823257530420752963450"

highest = 0
ubernumber.scan(/./).each_cons(5) do |group|
  product = group.map(&:to_i).reduce(:*)
  highest = product > highest ? product : highest
end
puts highest

numbers = <<CODE.gsub /\s*/, ''
73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450
CODE

puts numbers.split('').map(&:to_i).each_cons(5).map{|a| a.reduce(:*)}.max

@statianzo, I wish ruby had tail call optimization.