Easily print arguments passed to a `bash` script

printargs.sh

#!/usr/bin/env bash

#-------------------------------------------------------------------------------
#
#  print_args - easily inspect arguments passed to a bash script
#
#  sources:
#    https://unix.stackexchange.com/a/332126/183920
#
#-------------------------------------------------------------------------------

function print_args {

  echo "arguments:"

  local ii=1
  for arg; do
    printf "  \$%u: '%s'\n" "$ii" "$arg"
    ((ii++))
  done

}

# usage:
#
#   $ print_args 3 "3.a" "hello world"
#   arguments:
#     $1: '3'
#     $2: '3.a'
#     $3: 'hello world'

function example {

  echo "printing arguments passed to 'example'..."
  printargs "$@"
  echo "...done."

  printf "\$2 = %s\n" "$2"

}

# example:
#
#   $ example "a b" 5.5 ho-ho
#   printing arguments passed to 'example'...
#   arguments:
#     $1: 'a b'
#     $2: '5.5'
#     $3: 'ho-ho'
#   ...done.
#   $2 = 5.5