Check if a number is capicúa and if not, add its palindrome and check it again until n iterations given.

capicua.py

#!/usr/bin/env python3
from time import time as time
#Made by Ivan Gonzalez https://github.com/scratchmex (05/09/2017)
#Use python3
def reverse_number(n):
	n = str(n)
	return int(''.join([n[-i-1] for i in range(len(n))]))

def is_capicua(n):
	n = str(n)
	for i in range(len(n)//2):
		if n[i] is not n[-i-1]:
			return False
	return True

def process_numbers(numbers, max_iter, debug=False):
	start_time = time()
	proc_num = {}
	for number in numbers:
		i = 0
		num = number
		while i is not max_iter:
			if is_capicua(num):
				proc_num[number] = (i, num, 1)
				print('{} Done'.format(number), end='\r') if debug else None
				break
			else:
				prev_num, num = num, num + reverse_number(num)
				i += 1
		if i is max_iter:
			print('{} Reach limit'.format(number)) if debug else None
			proc_num[number] = (i, num, -1)
	global process_time
	process_time = time()-start_time
	print('This process took {} seconds'.format(process_time))
	return proc_num

def save_file(data, name):
	init_t = time()
	print('Starting saving...')
	with open(name, 'w') as f:
		f.write(data)
	print('Saved, this procces took {} seconds'.format(time()-init_t))

def format_save_cap(data, name):
	keys = data.keys()
	txt = '#Made by Ivan Gonzalez https://github.com/scratchmex (05/09/2017)\n'
	txt += 'This process took {} seconds\n\n'.format(process_time)
	print('Processing data...')
	for key in keys:
		if data[key][2] == 1:
			txt += 'Its capicua number of "{}" is "{}" in {} iterations\n'.format(key, data[key][1], data[key][0])
		elif data[key][2] == -1:
			txt += '"{}" has not capicua after {} iterations, I stayed in "{}"\n'.format(key, data[key][0], data[key][1])

	print('Done processing')
	save_file(txt, name)

def main(numbers, max_iter):
	format_save_cap(process_numbers(numbers, max_iter), '1milCapicuas.txt')

if __name__ == '__main__':
	main(range(1,10000+1), 100)