Created
April 17, 2012 12:15
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Levenshtein imp vs memo rec
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let levenshteinm (s:string) (t:string) = | |
let c = new Dictionary<_,_>() | |
let rec memo i j = | |
match c.TryGetValue((i,j)) with | |
| true, x -> x | |
| _ -> | |
let r = | |
match (i,j) with | |
| (i,0) -> i | |
| (0,j) -> j | |
| (i,j) -> | |
if s.[i-1] = t.[j-1] then memo (i-1) (j-1) | |
else | |
let d1, d2, d3 = memo (i-1) j, memo i (j-1), memo (i-1) (j-1) in | |
1 + min d1 (min d2 d3) | |
c.Add((i,j), r) | |
r | |
memo (String.length s) (String.length t) | |
let levenshteini (a:string) (b:string) : int = | |
let inline min3 (a:int) b c = min a (min b c) | |
match a.Length, b.Length with | |
| 0, m -> m | |
| n, 0 -> n | |
| n, m -> | |
// mutable excuse: it is internal and it avoids Array copy in favor of swap. | |
let mutable p = Array.init (n+1) id // previous | |
let mutable d = Array.create (n+1) 0 // current | |
for j = 1 to m do | |
let c = b.[j-1] | |
d.[0] <- j | |
for i = 1 to n do | |
let cost = if a.[i-1] = c then 0 else 1 | |
d.[i] <- min3 (d.[i-1] + 1) (p.[i] + 1) (p.[i-1] + cost) | |
let _d = p | |
p <- d | |
d <- _d | |
p.[n] |
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