Created
September 8, 2010 17:13
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input = [ 1, 2, 3, 4, 5, 8, 9, 11, 12, 13, 15 ] | |
# Need to box the value to make it mutable | |
State = Struct.new(:last_value) | |
def returning(value) yield; value; end | |
# divide the input into runs of consecutive numbers | |
s = input.slice_before(State.new(input.first)) do |value, state| | |
returning(value != state.last_value.succ) do | |
state.last_value = value | |
end | |
end | |
# replace runs of 3 or more with first-last | |
p s.map {|runs| runs.size < 3 ? runs : "#{runs.first}-#{runs.last}"} | |
.flatten | |
.join(', ') # => 1-5, 8, 9, 11-13, 15 |
Thanks for posting this, I made use of this example in a refactoring of the scoring koan that I posted here: http://gist.github.com/580960
Totally loving playing with ruby's Enumerable.
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I totally agree. I don't think this is a good example of how to use
slice_before
. But it's a great example of how to usereturning