Created
April 29, 2020 07:28
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| def find_first_in_list(objects, **kwargs): | |
| return next((obj for obj in objects if | |
| len(set(obj.keys()).intersection(kwargs.keys())) > 0 and | |
| all([obj[k] == v for k, v in kwargs.items() if k in obj.keys()])), | |
| None) |
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Usage:
obj = find_first_in_list(list_of_dict, name='Hello', key=23)If any key provided is not in keys of list of dict it is skipped. However, the function ensures there is at least one valid key used to compare. This implementation ensure you won't hit KeyError when passing an unknown key.