Created
September 20, 2021 22:07
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class Solution { | |
int[] ans, count; | |
List<Set<Integer>> graph; | |
int N; | |
public int[] sumOfDistancesInTree(int N, int[][] edges) { | |
this.N = N; | |
graph = new ArrayList<Set<Integer>>(); | |
ans = new int[N]; | |
count = new int[N]; | |
Arrays.fill(count, 1); | |
for (int i = 0; i < N; ++i) | |
graph.add(new HashSet<Integer>()); | |
for (int[] edge: edges) { | |
graph.get(Math.min(edge[0], edge[1])).add(Math.max(edge[0], edge[1])); | |
} | |
dfs(0, -1); | |
dfs2(0, -1); | |
return ans; | |
} | |
public void dfs(int node, int parent) { | |
for (int child: graph.get(node)) { | |
dfs(child, node); | |
count[node] += count[child]; | |
ans[node] += ans[child] + count[child]; | |
} | |
} | |
public void dfs2(int node, int parent) { | |
for (int child: graph.get(node)) { | |
ans[child] = ans[node] - count[child] + N - count[child]; | |
dfs2(child, node); | |
} | |
} | |
} |
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