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// Use Gists to store code you would like to remember later on | |
console.log(window); // log the "window" object to the console |
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static inline BOOL checkIfEmpty(id obj) { | |
return thing == nil || | |
([obj respondsToSelector:@selector(length)] && [(NSData *)obj length] == 0) || | |
([obj respondsToSelector:@selector(count)] && [(NSArray *)obj count] == 0); | |
} |
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#include <iostream> | |
using namespace std; | |
#include <stdlib.h> /* qsort */ | |
int compare (const void * a, const void * b) { | |
return ( *(int*)a - *(int*)b ); | |
} | |
int main4() | |
{ |
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#include <iostream> | |
using namespace std; | |
#include <stdlib.h> /* qsort */ | |
int compare (const void * a, const void * b) { | |
return ( *(int*)a - *(int*)b ); | |
} | |
int main() | |
{ |
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#include<iostream> | |
#include <list> | |
using namespace std; | |
class Graph { | |
int V; | |
list <int> * adj; | |
void DFSUtil(int v, bool visited[]); // A function used by DFS | |
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def calculateLevenSteninDistance(a,b): | |
if not a: return len(b) | |
if not b: return len(a) | |
return min(calculateLevenSteninDistance(a[1:], b[1:])+(a[0] != b[0]), calculateLevenSteninDistance(a[1:], b)+1, calculateLevenSteninDistance(a, b[1:])+1) |
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def findDivergePointForOfTwoLinkedLists(list1, list2): | |
# Assuming the list class has a method length to give the length of the list | |
lengthList1 = list1.length() | |
lengthList2 = list2.length() | |
differnce = lengthList2 - lengthList1 | |
if(lengthList2>=lengthList1): | |
while(differnce!=0): | |
list2 = list2.next | |
differnce -= 1 |
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def findLCA(node,value1,value2): | |
if(node == None): | |
return None | |
#move to right if values are greater | |
if(node.value < value1 and node.value < value2): | |
return findLCA(node.right,value1, value2) | |
#move to left if values are smaller | |
if(node.value > value1 and node.value > value2): | |
return findLCA(node.left,value1, value2) | |
# Whereever it diverges, return the node as its the LCA |
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''' | |
1 | |
2 3 | |
4 5 6 7 | |
should print 1,2,4,5,6,7,3,1 | |
''' |
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#max heap construction | |
def heapify(items,idx): | |
left = leftChild(idx) | |
right = rightChild(idx) | |
largest = -1 | |
if(left < len(items) and items[left] > items[idx]): | |
largest = left | |
else: | |
largest = idx |
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