solve an email address

a.py

import math


ps = [
  0.0000008110673199286165000000000000000000,
  0.0000162907226016170940000000000000000000,
  0.0024177576053697383000000000000000000000,
  0.0000000054649286143693143000000000000000,
  0.0003272079103201879800000000000000000000,
  0.0000000148552161462659780000000000000000,
  0.0065721465642952148000000000000000000000,
  0.0000000148552161462659780000000000000000,
  0.0000000000000000000000254604802054643040,
  0.0000059930219269618815000000000000000000,
  0.0065721465642952148000000000000000000000,
  0.9753930336921978700000000000000000000000,
  0.0008894433167514238800000000000000000000,
  0.0000000054649286143693143000000000000000,
  0.0000162907226016170940000000000000000000,
  0.0003272079103201879800000000000000000000,
  0.0000000000000000000000000000003877625978,
  0.0000000403806641082262080000000000000000,
  0.0065721465642952148000000000000000000000,
  0.0008894433167514238800000000000000000000,
]


if __name__ == '__main__':
  # minimum ascii character is '.'
  ascii_min = ord('.')
  p_min = min(ps)
  p_max = max(ps)
  # solver softmax parameter `max` and `sum`
  sf_sum = 1. / p_max
  sf_max = int(round(ascii_min - math.log(p_min * sf_sum)))
  # convert back
  email = ''
  for p in ps:
    ascii = int(round(math.log(p * sf_sum) + sf_max))
    ch = chr(ascii)
    email += ch
  print email