Created
December 11, 2019 09:15
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Daily Coding Problem: Problem #13
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# Given an integer k and a string s, find the length of the longest substring that contains at most k distinct characters. | |
# For example, given s = "abcba" and k = 2, the longest substring with k distinct characters is "bcb". | |
def finds(s, k) | |
arr = s.scan /\w/ | |
max = 0 | |
longest_word = '' | |
total_length = arr.length | |
last_idx = total_length - 1 | |
arr.each_with_index do |l, i| | |
p "first letter: #{l}" | |
start_slice = i | |
(i+1..last_idx).each do |j| | |
p "max: #{max}" | |
sub_array = arr.slice(i,j) | |
next if j + max > total_length | |
next if sub_array.length <= max | |
p "sub_array: #{sub_array}" | |
if sub_array.uniq.length <= k | |
if max < sub_array.length | |
longest_word = sub_array.join("") | |
max = sub_array.length | |
end | |
else | |
break | |
end | |
end | |
end | |
return longest_word | |
end | |
finds("abcba", 2) == "bcb" | |
finds("abcbavqerbcccbb", 2) == "bcccbb" |
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