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LinkedList ES6 Implementation
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class LinkedList { | |
constructor() { | |
this.head = null; | |
this.tail = null; | |
this.count = 0; | |
} | |
get length() { | |
return this.count; | |
} | |
addLast(data) { | |
// Create a new Node | |
const node = { | |
data: data, | |
next: null | |
} | |
if(this.count === 0) { | |
// If this is the first Node, assign it to head | |
this.head = node; | |
} else { | |
// If not the first node, link it to the last node | |
this.tail.next = node; | |
} | |
this.tail = node; | |
this.count++; | |
} | |
addFirst(data) { | |
// Create a new Node | |
const node = { | |
data: data, | |
next: null | |
} | |
// Save the first Node | |
const temp = this.head; | |
// Point head to the new Node | |
this.head = node; | |
// Add the rest of node behind the new first Node | |
this.head.next = temp; | |
this.count++; | |
if(this.count === 1) { | |
// If first node, | |
// point tail to it as well | |
this.tail = this.head; | |
} | |
} | |
removeFirst(data) { | |
if(this.count > 0) { | |
// The head should point to the second element | |
this.head = this.head.next; | |
this.count--; | |
if(this.count === 0) { | |
// If list empty, set tail to null | |
this.tail = null; | |
} | |
} | |
} | |
removeLast(data) { | |
if(this.count > 0) { | |
if(this.count === 1) { | |
this.head = null; | |
this.tail = null; | |
} else { | |
// Find the Node right before the last Node | |
let current = this.head; | |
while(current.next !== this.tail) { | |
current = current.next; | |
} | |
current.next = null; | |
this.tail = current; | |
} | |
this.count--; | |
} | |
} | |
} |
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data
arguments ofremoveLast
andremoveFirst
look unneeded.