A bash script expects rust filename then compiles, executes & deletes binary to automate the process

rust.sh

#!/bin/bash

HELP_MENU="Usage: ${0##*/} [-h|--help] <rust_filename>
Compile and run a Rust file, then delete the binary.

Options:
  -h, --help  Show this help menu
"

if [ $# -eq 0 ]; then
  echo "Error: Rust filename is required"
  echo "$HELP_MENU"
  exit 1
fi

while [ $# -gt 0 ]; do
  case "$1" in
    -h|--help)
      echo "$HELP_MENU"
      exit 0
      ;;
    *)
      RUST_FILENAME="$1"
      ;;
  esac
  shift
done

if [ ! -f "$RUST_FILENAME" ]; then
  echo "Error: File '$RUST_FILENAME' does not exist"
  exit 1
fi

rustc "$RUST_FILENAME"
if [ $? -ne 0 ]; then
  echo "Error: Compilation failed"
  exit 1
fi

BIN_FILENAME="${RUST_FILENAME%.rs}"
./"$BIN_FILENAME"
rm "$BIN_FILENAME"

Let me explain how the script works:

1. The script checks if no arguments are provided, and if so, shows an error message and the help menu.
2. The script then loops through the command-line arguments. If the -h or --help flag is provided, it shows the help menu and exits.
3. Otherwise, it assumes the first argument is the Rust filename and stores it in the RUST_FILENAME variable.
4. The script checks if the file exists, and if not, shows an error message and exits.
5. The script compiles the Rust file using rustc. If the compilation fails, it shows an error message and exits.
6. If the compilation succeeds, the script runs the generated binary using ./<binary_name>.
7. Finally, the script deletes the binary using rm.