Check if WannaCry SinkHole is reachable, as per its code.

wanna_sink_check.py

from __future__ import print_function

import ctypes

DLL_KERNEL32 = ctypes.windll.kernel32
DLL_WININET = ctypes.windll.wininet

handle_inet = DLL_WININET.InternetOpenA(None, 1, None, None, None)
response = DLL_WININET.InternetOpenUrlA(
    handle_inet,
    'http://iuqerfsodp9ifjaposdfjhgosurijfaewrwergwea.com/',
    None,
    None,
    0x84000000,
    None)

if response:
    print('SinkHole reachable')
    DLL_WININET.InternetCloseHandle(response)
else:
    print('SinkHole NOT reachable!!')

DLL_WININET.InternetCloseHandle(handle_inet)

Slight change to the module definitions for Python 3. Hope this helps someone.

from urllib.request import urlopen
from urllib.error import URLError

url = 'http://iuqerfsodp9ifjaposdfjhgosurijfaewrwergwea.com/'

def sinkholetest(endpoint):
    try:
        urlopen(endpoint).read()
        print ('WannaCry Sinkhole was reached')
    except URLError as e:
        print ('WannaCry Sinkhole not reachable')
    return

sinkholetest(url)