Bresson bresson

Monolith

The Ball Of Mud represents the worst case scenario for a Monolith. Also called as Spaghetti Code.
No clear isolation in the application.
Complex dependencies where everything depends on every other thing.
Hard to understand and harder to modify.

To clean up the ball of mud we introduce isolation into the application by dividing the application along clear domain boundaries.
We introduce packages and libraries that help isolate related pieces of code. They provide a clean and consistent interface.

	FROM ubuntu:20.04

	ENV DEBIAN_FRONTEND=noninteractive

	RUN apt-get update && \
	apt-get install -y \
	pkg-config \
	curl \
	libfreetype6-dev \
	libc6-dev \

	% Erlang "take" function in direct and tail recursion

	-module(take).
	-export([take/2, tctake/2, test_tctake/0]).

	take(0,_) -> [];

	take(_, []) -> [];

	take(N, [X \| _Xs]) ->

	<!doctype html>
	<html lang="en">
	<head>
	<meta charset="utf-8">
	<title>GistRun</title>
	<link rel="stylesheet" href="styles.css">

	</head>
	<body>
	<div id="content">

	<!doctype html>
	<html lang="en">
	<head>
	<meta charset="utf-8">
	<title>GistRun</title>
	<link rel="stylesheet" href="styles.css">
	</head>
	<body>
	<div id="content">
	<svg width="400px" height="400px">

	% frequency server enhancements using list comprehension
	% My first instinct was to solve this problem through recursion. However, I decided to use list comprehension / filter just to sample a new flavor. With list comprehension, I was able to pattern match but the process felt more like checking the length of the Frequencies/allocated list to determine if the request was valid.% If anyone can provide a hint, I had to create two functions, is_allocated and is_deallocated, the first to check if the Pid is already allocated a frequency and the second to check if a requested deallocate frequency was in fact allocated. The functions are very similar and should be one function. However, I couldn't figure out how to pass in a parameter that will inform the following line to check Client == Y or Client == X
	% [X \|\| {X, Y} <- Allocated, Client == Y].

	init() ->
	Frequencies = {get_frequencies(), []},
	loop(Frequencies).

	% Hard Coded
	get_frequencies() -> [10,11,12,13,14,15].

	// experiment of functional composition


	const addOne = a => a + 1;
	const double = a => a * 2;
	const square = a => a * a;

	const lCompose = (...args) => {

	const _lCompose = ( acc, ...args ) => {

	// easing functions http://goo.gl/5HLl8
	Math.easeInOutQuad = function (t, b, c, d) {
	t /= d/2;
	if (t < 1) {
	return c/2tt + b
	}
	t--;
	return -c/2 * (t*(t-2) - 1) + b;
	};