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An array is cast to a pointer when passed as a parameter to a function
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| #include <stdio.h> | |
| void initialize_array(int arr[], int val); | |
| int main() | |
| { | |
| int arr[30]; | |
| initialize_array(arr, 5); | |
| int n = sizeof(arr) / sizeof(arr[0]); | |
| printf("n = %d\n", n); | |
| printf("sizeof(arr) = %lu\n", sizeof(arr)); | |
| printf("sizeof(arr[0]) = %lu\n", sizeof(arr[0])); | |
| //for (int i=0; i<n; i++) | |
| //{ | |
| //printf("arr[%d] = %d\n", i, arr[i]); | |
| //} | |
| return 0; | |
| } | |
| void initialize_array(int arr[], int val) | |
| { | |
| int n = sizeof(arr) / sizeof(arr[0]); | |
| printf("n = %d\n", n); | |
| printf("sizeof(arr) = %lu\n", sizeof(arr)); | |
| printf("sizeof(arr[0]) = %lu\n", sizeof(arr[0])); | |
| for (int i=0; i<n; i++) | |
| { | |
| arr[i] = val; | |
| } | |
| } |
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