java8FunctionAdapters.scala

// fully qualified Java clases deliberately, so it screams THIS IS FOR JAVA
// please excuse ASCII art for readability of very similar functions

implicit def toJavaConsumer[T]       (con: T=>Unit)    = new java.util.function.Consumer[T]       { def accept(t:T) = con(t) } 
implicit def toJavaBiConsumer[A,B]   (con: (A,B)=>_)   = new java.util.function.BiConsumer[A,B]   { def accept(a:A,b:B) = con(a,b) } 
implicit def toJavaSupplier[T]       (sup: Unit=>T)    = new java.util.function.Supplier[T]       { def get(): T = sup() }
implicit def toJavaFunction[T,R]     (fun: T=>R)       = new java.util.function.Function[T,R]     { def apply(t:T) = fun(t) } 
implicit def toJavaBiFunction[T,U,R] (fun: (T,U)=>R)   = new java.util.function.BiFunction[T,U,R] { def apply(t:T, u:U) = fun(t, u) } 

implicit def consumerToScala[T]    (con: java.util.function.Consumer[T]):       T=>Unit     = con.accept
implicit def biconsumerToScala[A,B](fun: java.util.function.BiConsumer[A,B]):   (A,B)=>Unit = fun.accept
implicit def supplierToScala[T]    (sup: java.util.function.Supplier[T]):       Unit=>T     = sup.get
implicit def func1ToScala[T,R]     (fun: java.util.function.Function[T,R]):     T=>R        = fun
implicit def func2ToScala[T,U,R]   (fun: java.util.function.BiFunction[T,U,R]): (T,U)=>R    = fun