Kotlin initializer order example

example.kt

open class Parent {
    private val a = println("Parent.a")

    constructor(arg: Unit=println("Parent primary constructor default argument")) {
        println("Parent primary constructor")
    }

    init {
        println("Parent.init")
    }

    private val b = println("Parent.b")
}

class Child : Parent {
    val a = println("Child.a")

    init {
        println("Child.init 1")
    }

    constructor(arg: Unit=println("Child primary constructor default argument")) : super() {
        println("Child primary constructor")
    }

    val b = println("Child.b")

    constructor(arg: Int, arg2:Unit= println("Child secondary constructor default argument")): this() {
        println("Child secondary constructor")
    }

    init {
        println("Child.init 2")
    }
}

maybe add some lazy initialization?

fun main(args: Array<String>) {
    Child().lazyVal
}

open class Parent {
    private val a = println("Parent.a")
    
    public val lazyVal by lazy {
        println("Parent.lazy")
    }
.......

Here's the output from ideone.com:

Child primary constructor default argument
Parent primary constructor default argument
Parent.a
Parent.init
Parent.b
Parent primary constructor
Child.a
Child.init 1
Child.b
Child.init 2
Child primary constructor