Tic Tac Toe in python in a 4 iteration for loop

tic_tac_toe.py

# import only system from os
from os import system, name
import math

# define our clear function
def clear():
  
    # for windows
    if name == 'nt':
        _ = system('cls')
  
    # for mac and linux(here, os.name is 'posix')
    else:
        _ = system('clear')


# converted to regular array because dictionaries are annoying
board   = [' '] * 9 # marks the game spots
board_x = [  0] * 9 # holds player X's spots
board_o = [  0] * 9 # holds player O's spots

def print_board(board):
    #clear()
    print(f"1:[{board[0]}] | 2:[{board[1]}] | 3:[{board[2]}] ")
    print('------+-------+------')
    print(f"4:[{board[3]}] | 5:[{board[4]}] | 6:[{board[5]}] ")
    print('------+-------+------')
    print(f"7:[{board[6]}] | 8:[{board[7]}] | 9:[{board[8]}] ")
 

# gets and validate input, looping if input is not valid
def get_input(turn):
    while True:
      try:
        print(f"\nIt's your turn {turn} [1-9]: ", end='')
        move = int(input())-1 # 1-based to 0-based
        print(f"selected: {move}")
        #check first if its within bounds
        if(move < 0 or move > 8): #internal is 0-based, display is 1-based
            print("It is not a valid number, use 1 to 9 only.")
            continue

        #test if the spot was not taken
        if(board[move] == ' '):
            board[move] = turn
            player_board = board_x if (turn == 'X') else board_o
            player_board[move] = 10 #any nonzero number
            return move
            
        print("That place is already filled, try again.")

      except ValueError:
        print("It is not a valid number, use 1 to 9 only. Try again") #this could be a specific error for "the input was not parsed as number"
        continue
        
        
def check_win(turn):
    player_board = board_x if (turn == 'X') else board_o

    y = 0
    # reads the player board, multiplies all the spots together 3-line by 3-line, if any of the
    # tested line has any spot == 0, the result of the multiplication is 0
    # if any of the lines is NOT zero, then that line is filled by this player
    
    for x in range(1, 5): # 1, 2, 3, 4 bcz off by one (thankyou python! )
        # takes the middle spot, adds the same index in postive and negative 
        # gets the diagonal, center vertical, second diagonal and middle horizontal
        y += player_board[4-x] * player_board[4] * player_board[4+x]
        #checks the outer lines: top horizontal, left vertical, right vertical, bottom horizontal
        other    = x+(x-1)
        distance = 1+(2*(math.floor(other/3) % 2))
        y += player_board[other-distance] * player_board[other] * player_board[other+distance]
    return y!=0

def main():
    turn = 'X'
    counter = 0
    clear()

    for i in range(9):
        print_board(board)
        move = get_input(turn)
        clear()

        counter += 1 
        has_won = check_win(turn)
        if(has_won): 
            print_board(board)
            print(f"Player {turn} has won!")
            return
 
        turn = ['X', 'O'][counter % 2] 
    print("Nobody won, its a tie")
 
if __name__ == "__main__":
    main()