Search In Rotated Sorted Array LeetCode

searchInRotatedSortedArray.js

/*
There is an integer array nums sorted in ascending order (with distinct values).
Prior to being passed to your function, nums is rotated at an unknown pivot index k (0 <= k < nums.length) such that the resulting array is [nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1], ..., nums[k-1]] (0-indexed). For example, [0,1,2,4,5,6,7] might be rotated at pivot index 3 and become [4,5,6,7,0,1,2].
Given the array nums after the rotation and an integer target, return the index of target if it is in nums, or -1 if it is not in nums.
You must write an algorithm with O(log n) runtime complexity.
 
Example 1:
Input: nums = [4,5,6,7,0,1,2], target = 0
Output: 4
Example 2:
Input: nums = [4,5,6,7,0,1,2], target = 3
Output: -1
Example 3:
Input: nums = [1], target = 0
Output: -1
 
Constraints:
1 <= nums.length <= 5000
-104 <= nums[i] <= 104
All values of nums are unique.
nums is guaranteed to be rotated at some pivot.
-104 <= target <= 104
*/

const nums = [4,5,6,7,0,1,2], target = 0;

/**
 * @param {number[]} nums
 * @param {number} target
 * @return {number}
 */
 var search = function(nums, target) {
    for (let i = 0; i < nums.length; i++) {
        if (nums[i] === target) {
            return i;
        }
    }
    return -1;
};

console.log(search(nums, target));