iOS Debug display image function

gistfile1.m

/**
 * @discussion takes the passed image parameter and displays a view controller modally that shwos the image
 * You can call it from the debugger like this:
 * expr JSDebugDisplayImage(image)
 * @note you can dismiss the view controller simply by tapping on it
 */
extern void JSDebugDisplayImage(UIImage *image);

gistfile2.m

@interface JSDebugDisplayImageViewController : UIViewController

- (id)initWithImage:(UIImage *)image;

@property (nonatomic, strong) UIImage *image;
@property (nonatomic, weak) UIImageView *imageView;

@end

@implementation JSDebugDisplayImageViewController

- (id)initWithImage:(UIImage *)image
{
    if ((self = [super init]))
    {
        self.image = image;
    }

    return self;
}

- (void)loadView
{
    [super loadView];

    self.imageView = [[UIImageView alloc] initWithImage:self.image];
    self.imageView.frame = self.view.bounds;
    self.imageView.autoresizingMask = UIViewAutoresizingFlexibleWidth | UIViewAutoresizingFlexibleHeight;
    self.imageView.contentMode = UIViewContentModeScaleAspectFit;

    [self.view addSubview:self.imageView];
}

- (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event
{
    [self dismissViewControllerAnimated:YES completion:nil];
}

@end

void JSDebugDisplayImage(UIImage *image)
{
    JSDebugDisplayImageViewController *imageVC = [[JSDebugDisplayImageViewController alloc] initWithImage:image];

    [[UIApplication sharedApplication].keyWindow.rootViewController presentViewController:imageVC animated:YES completion:nil];
}