Created
May 29, 2021 05:35
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class Solution { | |
// Hash table that takes care of the mappings. | |
private HashMap<Character, Character> mappings; | |
// Initialize hash map with mappings. This simply makes the code easier to read. | |
public Solution() { | |
this.mappings = new HashMap<Character, Character>(); | |
this.mappings.put(')', '('); | |
this.mappings.put('}', '{'); | |
this.mappings.put(']', '['); | |
} | |
public boolean isValid(String s) { | |
// Initialize a stack to be used in the algorithm. | |
Stack<Character> stack = new Stack<Character>(); | |
for (int i = 0; i < s.length(); i++) { | |
char c = s.charAt(i); | |
// If the current character is a closing bracket. | |
if (this.mappings.containsKey(c)) { | |
// Get the top element of the stack. If the stack is empty, set a dummy value of '#' | |
char topElement = stack.empty() ? '#' : stack.pop(); | |
// If the mapping for this bracket doesn't match the stack's top element, return false. | |
if (topElement != this.mappings.get(c)) { | |
return false; | |
} | |
} else { | |
// If it was an opening bracket, push to the stack. | |
stack.push(c); | |
} | |
} | |
// If the stack still contains elements, then it is an invalid expression. | |
return stack.isEmpty(); | |
} | |
} |
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