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December 13, 2016 05:26
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Swift: combining varargs and autoclosure
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// This compiles: | |
func immediateOr(args:Bool...) -> Bool { | |
for arg in args { | |
if arg { | |
return true | |
} | |
} | |
return false | |
} | |
// A. This doesn't compile: | |
func lazyOr(args: @autoclosure() -> Bool...) -> Bool { | |
for arg in args { // "Error: Function produces expected type '[@autoclosure() -> Bool]'" | |
if arg() { | |
return true | |
} | |
} | |
return false | |
} | |
// B. This doesn't compile (typealias): | |
typealias LazyPredicate = @autoclosure() -> Bool | |
func lazyOr(args: LazyPredicate...) -> Bool { | |
for arg in args { // "Error: Function produces expected type '[@autoclosure() -> Bool]'" | |
if arg() { | |
return true | |
} | |
} | |
return false | |
} | |
// C. This doesn't compile (parenthesize): | |
func lazyOr(args: (@autoclosure() -> Bool)...) -> Bool { | |
for arg in args { // "Error: Function produces expected type '[@autoclosure() -> Bool]'" | |
if arg() { | |
return true | |
} | |
} | |
return false | |
} | |
// D. This "works"... | |
func lazyOr(args: (@autoclosure() -> Bool, Int)...) -> Bool { | |
for arg in args { | |
if arg.0() { | |
return true | |
} | |
} | |
return false | |
} | |
lazyOr((expensiveA(), 42), (expensiveB(), 42)) |
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I was excited when I saw the comment by @vivekseth, but I've now tried it and it looks like it doesn't work with Swift 3.