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BASH script to find the newest file under a directory structure
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| #!/bin/bash | |
| if [[ "x${1}" == "x" ]]; then | |
| dir="." | |
| else | |
| dir="${1}" | |
| fi | |
| find "${dir}" -type f -printf "%C@ %p\n" | sort -rn | head -n 1 | cut -d' ' -f2 | xargs ls -l | cut -d' ' -f6,7,8 |
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